Quote:
<?php
$today = date("d");
$thisMonth = date("M");
$thisYear = date("Y");
echo date("M d Y", mktime(0,0,0, $thisMonth, $today, $today-8));
?>
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this is wrong for so many reasons beyond just having your mktime parameters screwed up
how about when your $today-8 is an invalid day value? on the 7th $day-8 comes back as -1
also what is with splitting the date into pieces like that? you were doing that in the database table at one point too.
you are taking your date and converting it to 3 integers and then turning it back into a date, why?
every language has date functions to handle date calculations, php included
https://www.w3schools.com/php/php_ref_date.asp
handling it the way you are doing is basically trying to reinvent the wheel
Quote:
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echo date("M d Y", time() - (86400 * 8));
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that is a reasonable solution
i prefer to use datetime objects
in php you can add and subtract from a date pretty easily using the datetime object and associated functions
$mydate=date_create(date('Y-m-d',time())); // create the datetime object
date_sub($mydate, date_interval_create_from_date_string("8 days")); // subtract 8 days
echo date_format($mydate,"M d Y"); // display the result
https://www.w3schools.com/php/func_date_date_sub.asp
you could also use date_modify() for this
$date=date_create(date('Y-m-d',time()));
date_modify($date,"-8 days");
echo date_format($date,"Y-m-d");
https://www.w3schools.com/php/func_date_modify.asp
you should, at all times while working on this stuff have a browser window open to php.net and w3schools.com or other coding sites, just my opinion
.